8y^2-8y=48

Solution for 8y^2-8y=48 equation:

8y^2-8y=48

We move all terms to the left:

8y^2-8y-(48)=0

a = 8; b = -8; c = -48;
Δ = b2-4ac
Δ = -82-4·8·(-48)
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1600}=40$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-40}{2*8}=\frac{-32}{16}
=-2
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+40}{2*8}=\frac{48}{16}
=3
$